.0825t^2-0.914t+1.788=0

Solution for .0825t^2-0.914t+1.788=0 equation:

.0825t^2-0.914t+1.788=0

a = .0825; b = -0.914; c = +1.788;
Δ = b2-4ac
Δ = -0.9142-4·.0825·1.788
Δ = 0.245356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.914)-\sqrt{0.245356}}{2*.0825}=\frac{0.914-\sqrt{0.245356}}{0.165}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.914)+\sqrt{0.245356}}{2*.0825}=\frac{0.914+\sqrt{0.245356}}{0.165}
$